Caches: Calculate the Number of Offset Bits
Date: 2014-11-05 |
DISCLOSURE: If you buy through affiliate links, I may earn a small commission. (disclosures)
The number of offset bits required in a cache is dependent on the number of addressable locations in one data block. If there are 2^n locations in a block, then you need n offset bits to identify all of the locations inside the given block.
**Example: **Given a cache where the size of a data block is 4 bytes and the architecture is byte-addressable, you must have enough offset bits to address 4 different locations. 4 = 2^2, therefore you need 2 offset bits to address all locations in a block.
Want more like this?
The best way to support my work is to like / comment / share for the algorithm and subscribe for future updates.