Calculus: Evaluate the Double Integral
Date: 2013-11-18 |
**Evaluate the integral ∫1-2 **∫y-y^2 dxdy <– That’s not a typo, there’s no given function to integrate
**Solution: **Start by integrating with x. In this case, it basically means skipping integration and plugging in the bounds as if there were an x variable.
∫1-2 y^2 – y dy
Integrating with y gives us:
(y<>3)/3 – (y2)/2|1-2 => 8/3 – 4/2 – (1/3 – 1/2)
Simplify this to get:
Answer: 5/6
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