Calculus: Compute a Schur Factorization of the Matrix
Date: 2013-11-12 |
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**Compute a Schur Factorization of the matrix A = **
-3 | 4 |
-6 | 7 |
By normalizing this eigenvector, we get U1 = (1/sqrt(2))(1,1)
From U1, we get U2 = vector perpendicular to U1 = (1/sqrt(2))(-1,1)
Q = (U1, U2) =
1/sqrt(2) | -1/sqrt(2) |
1/sqrt(2) | 1/sqrt(2) |
1/sqrt(2) | 1/sqrt(2) |
-1/sqrt(2) | 1/sqrt(2) |
**T = **
1 | 10 |
0 | 3 |
1/sqrt(2) | -1/sqrt(2) |
1/sqrt(2) | 1/sqrt(2) |
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